4x-100x^2=0

Solution for 4x-100x^2=0 equation:

4x-100x^2=0

a = -100; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-100)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-100}=\frac{-8}{-200}
=1/25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-100}=\frac{0}{-200}
=0
$